abs(3x^2+7x+3)=1

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Solution for abs(3x^2+7x+3)=1 equation: 


Simplifying
abs(3x2 + 7x + 3) = 1

Reorder the terms:
abs(3 + 7x + 3x2) = 1
(3 * abs + 7x * abs + 3x2 * abs) = 1
(3abs + 7absx + 3absx2) = 1

Solving
3abs + 7absx + 3absx2 = 1

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Reorder the terms:
-1 + 3abs + 7absx + 3absx2 = 1 + -1

Combine like terms: 1 + -1 = 0
-1 + 3abs + 7absx + 3absx2 = 0

The solution to this equation could not be determined.

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